NCERT Solutions for Class 12 Maths Chapter 5 – Continuity and Differentiability Ex 5.2
Page No 166:
Question 1:
Differentiate the functions with respect to x.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6853/Chapter%205_html_m4d909628.gif)
Answer:
Let f(x)=sinx2+5, ux=x2+5, and v(t)=sint
Then, vou=vux=vx2+5=tanx2+5=f(x)
Thus, f is a composite of two functions.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6853/Chapter%205_html_m76e301f4.gif)
Alternate method
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6853/Chapter%205_html_7e76c191.gif)
Question 2:
Differentiate the functions with respect to x.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6856/Chapter%205_html_m73e47a83.gif)
Answer:
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6856/Chapter%205_html_m26cdca88.gif)
Thus, f is a composite function of two functions.
Put t = u (x) = sin x
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6856/Chapter%205_html_4ceae8bd.gif)
By chain rule,![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6856/Chapter%205_html_m119d5d9e.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6856/Chapter%205_html_m119d5d9e.gif)
Alternate method
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6856/Chapter%205_html_664cfa69.gif)
Question 3:
Differentiate the functions with respect to x.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6858/Chapter%205_html_me9e6b3b.gif)
Answer:
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6858/Chapter%205_html_m4ff198ec.gif)
Thus, f is a composite function of two functions, u and v.
Put t = u (x) = ax + b
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6858/Chapter%205_html_7838a27b.gif)
Hence, by chain rule, we obtain
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6858/Chapter%205_html_e4e4928.gif)
Alternate method
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6858/Chapter%205_html_5e6626a8.gif)
Question 4:
Differentiate the functions with respect to x.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6860/Chapter%205_html_m39f8d27b.gif)
Answer:
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6860/Chapter%205_html_714e4461.gif)
Thus, f is a composite function of three functions, u, v, and w.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6860/Chapter%205_html_m27e732b4.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6860/Chapter%205_html_6bc2354c.gif)
Hence, by chain rule, we obtain
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6860/Chapter%205_html_21a687a3.gif)
Alternate method
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6860/Chapter%205_html_2ba7a7d4.gif)
Question 5:
Differentiate the functions with respect to x.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6862/Chapter%205_html_m74aa0a8b.gif)
Answer:
The given function is
, where g (x) = sin (ax + b) and
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6862/Chapter%205_html_85ef1b7.gif)
h (x) = cos (cx + d)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6862/Chapter%205_html_55c8a329.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6862/Chapter%205_html_2129c4ad.gif)
∴ g is a composite function of two functions, u and v.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6862/Chapter%205_html_56dd424a.gif)
Therefore, by chain rule, we obtain
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6862/Chapter%205_html_m5cf33a7.gif)
∴h is a composite function of two functions, p and q.
Put y = p (x) = cx + d
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6862/Chapter%205_html_71b91de8.gif)
Therefore, by chain rule, we obtain
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6862/Chapter%205_html_7b73ba25.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6862/Chapter%205_html_695dd5a1.gif)
Question 6:
Differentiate the functions with respect to x.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6865/Chapter%205_html_5333257e.gif)
Answer:
The given function is
.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6865/Chapter%205_html_5333257e.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6865/Chapter%205_html_2f2abb3d.gif)
Question 7:
Differentiate the functions with respect to x.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6866/Chapter%205_html_728931d9.gif)
Answer:
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6866/Chapter%205_html_231350d7.gif)
Question 8:
Differentiate the functions with respect to x.
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6869/Chapter%205_html_m69c04209.gif)
Answer:
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6869/Chapter%205_html_38a98fe8.gif)
Clearly, f is a composite function of two functions, u and v, such that
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6869/Chapter%205_html_m18ee6d2d.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6869/Chapter%205_html_7147c9af.gif)
By using chain rule, we obtain
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6869/Chapter%205_html_me24073e.gif)
Alternate method
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6869/Chapter%205_html_61c17f97.gif)
Question 9:
Prove that the function f given by
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6873/Chapter%205_html_m1a89e7ec.gif)
Answer:
The given function is![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6873/Chapter%205_html_m1a89e7ec.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6873/Chapter%205_html_m1a89e7ec.gif)
It is known that a function f is differentiable at a point x = c in its domain if both
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6873/Chapter%205_html_m246fba49.gif)
To check the differentiability of the given function at x = 1,
consider the left hand limit of f at x = 1
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6873/Chapter%205_html_m169cbd00.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6873/Chapter%205_html_m274af491.gif)
Since the left and right hand limits of f at x = 1 are not equal, f is not differentiable at x = 1
Question 10:
Prove that the greatest integer function defined by
is not
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6875/Chapter%205_html_2ba7aba7.gif)
differentiable at x = 1 and x = 2.
Answer:
The given function f is![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6875/Chapter%205_html_2ba7aba7.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6875/Chapter%205_html_2ba7aba7.gif)
It is known that a function f is differentiable at a point x = c in its domain if both
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6875/Chapter%205_html_m246fba49.gif)
To check the differentiability of the given function at x = 1, consider the left hand limit of f at x = 1
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6875/Chapter%205_html_5dc0d8f0.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6875/Chapter%205_html_7bb8909e.gif)
Since the left and right hand limits of f at x = 1 are not equal, f is not differentiable at
x = 1
To check the differentiability of the given function at x = 2, consider the left hand limit
of f at x = 2
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6875/Chapter%205_html_6d34caac.gif)
![](https://img-nm.mnimgs.com/img/study_content/curr/1/12/15/234/6875/Chapter%205_html_14d07761.gif)
Since the left and right hand limits of f at x = 2 are not equal, f is not differentiable at x = 2