NCERT Solutions for Class 11 Maths Chapter 11 – Conic Sections Ex 11.3
Page No 255:
Question 1:
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse
Answer:
The given equation is.
Here, the denominator of is greater than the denominator of.
Therefore, the major axis is along the x-axis, while the minor axis is along the y-axis.
On comparing the given equation with, we obtain a = 6 and b = 4.
Therefore,
The coordinates of the foci are.
The coordinates of the vertices are (6, 0) and (–6, 0).
Length of major axis = 2a = 12
Length of minor axis = 2b = 8
Length of latus rectum
Question 2:
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse
Answer:
The given equation is.
Here, the denominator of is greater than the denominator of.
Therefore, the major axis is along the y-axis, while the minor axis is along the x-axis.
On comparing the given equation with, we obtain b = 2 and a = 5.
Therefore,
The coordinates of the foci are.
The coordinates of the vertices are (0, 5) and (0, –5)
Length of major axis = 2a = 10
Length of minor axis = 2b = 4
Length of latus rectum
Question 3:
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse
Answer:
The given equation is.
Here, the denominator of is greater than the denominator of.
Therefore, the major axis is along the x-axis, while the minor axis is along the y-axis.
On comparing the given equation with, we obtain a = 4 and b = 3.
Therefore,
The coordinates of the foci are.
The coordinates of the vertices are.
Length of major axis = 2a = 8
Length of minor axis = 2b = 6
Length of latus rectum
Question 4:
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse
Answer:
The given equation is.
Here, the denominator of is greater than the denominator of.
Therefore, the major axis is along the y-axis, while the minor axis is along the x-axis.
On comparing the given equation with, we obtain b = 5 and a = 10.
Therefore,
The coordinates of the foci are.
The coordinates of the vertices are (0, ±10).
Length of major axis = 2a = 20
Length of minor axis = 2b = 10
Length of latus rectum
Question 5:
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse
Answer:
The given equation is.
Here, the denominator of is greater than the denominator of.
Therefore, the major axis is along the x-axis, while the minor axis is along the y-axis.
On comparing the given equation with, we obtain a = 7 and b = 6.
Therefore,
The coordinates of the foci are.
The coordinates of the vertices are (± 7, 0).
Length of major axis = 2a = 14
Length of minor axis = 2b = 12
Length of latus rectum
Question 6:
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse
Answer:
The given equation is.
Here, the denominator of is greater than the denominator of.
Therefore, the major axis is along the y-axis, while the minor axis is along the x-axis.
On comparing the given equation with, we obtain b = 10 and a = 20.
Therefore,
The coordinates of the foci are.
The coordinates of the vertices are (0, ±20)
Length of major axis = 2a = 40
Length of minor axis = 2b = 20
Length of latus rectum
Question 7:
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse 36x2 + 4y2 = 144
Answer:
The given equation is 36x2 + 4y2 = 144.
It can be written as
Here, the denominator of is greater than the denominator of.
Therefore, the major axis is along the y-axis, while the minor axis is along the x-axis.
On comparing equation (1) with, we obtain b = 2 and a = 6.
Therefore,
The coordinates of the foci are.
The coordinates of the vertices are (0, ±6).
Length of major axis = 2a = 12
Length of minor axis = 2b = 4
Length of latus rectum
Question 8:
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse 16x2 + y2 = 16
Answer:
The given equation is 16x2 + y2 = 16.
It can be written as
Here, the denominator of is greater than the denominator of.
Therefore, the major axis is along the y-axis, while the minor axis is along the x-axis.
On comparing equation (1) with, we obtain b = 1 and a = 4.
Therefore,
The coordinates of the foci are.
The coordinates of the vertices are (0, ±4).
Length of major axis = 2a = 8
Length of minor axis = 2b = 2
Length of latus rectum
Question 9:
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse 4x2 + 9y2 = 36
Answer:
The given equation is 4x2 + 9y2 = 36.
It can be written as
Here, the denominator of is greater than the denominator of.
Therefore, the major axis is along the x-axis, while the minor axis is along the y-axis.
On comparing the given equation with, we obtain a = 3 and b = 2.
Therefore,
The coordinates of the foci are.
The coordinates of the vertices are (±3, 0).
Length of major axis = 2a = 6
Length of minor axis = 2b = 4
Length of latus rectum
Question 10:
Find the equation for the ellipse that satisfies the given conditions: Vertices (±5, 0), foci (±4, 0)
Answer:
Vertices (±5, 0), foci (±4, 0)
Here, the vertices are on the x-axis.
Therefore, the equation of the ellipse will be of the form, where a is the semi-major axis.
Accordingly, a = 5 and c = 4.
It is known that.
Thus, the equation of the ellipse is.
Question 11:
Find the equation for the ellipse that satisfies the given conditions: Vertices (0, ±13), foci (0, ±5)
Answer:
Vertices (0, ±13), foci (0, ±5)
Here, the vertices are on the y-axis.
Therefore, the equation of the ellipse will be of the form, where a is the semi-major axis.
Accordingly, a = 13 and c = 5.
It is known that.
Thus, the equation of the ellipse is.
Question 12:
Find the equation for the ellipse that satisfies the given conditions: Vertices (±6, 0), foci (±4, 0)
Answer:
Vertices (±6, 0), foci (±4, 0)
Here, the vertices are on the x-axis.
Therefore, the equation of the ellipse will be of the form, where a is the semi-major axis.
Accordingly, a = 6, c = 4.
It is known that.
Thus, the equation of the ellipse is.
Question 13:
Find the equation for the ellipse that satisfies the given conditions: Ends of major axis (±3, 0), ends of minor axis (0, ±2)
Answer:
Ends of major axis (±3, 0), ends of minor axis (0, ±2)
Here, the major axis is along the x-axis.
Therefore, the equation of the ellipse will be of the form, where a is the semi-major axis.
Accordingly, a = 3 and b = 2.
Thus, the equation of the ellipse is.
Question 14:
Find the equation for the ellipse that satisfies the given conditions: Ends of major axis, ends of minor axis (±1, 0)
Answer:
Ends of major axis, ends of minor axis (±1, 0)
Here, the major axis is along the y-axis.
Therefore, the equation of the ellipse will be of the form, where a is the semi-major axis.
Accordingly, a = and b = 1.
Thus, the equation of the ellipse is.
Question 15:
Find the equation for the ellipse that satisfies the given conditions: Length of major axis 26, foci (±5, 0)
Answer:
Length of major axis = 26; foci = (±5, 0).
Since the foci are on the x-axis, the major axis is along the x-axis.
Therefore, the equation of the ellipse will be of the form, where a is the semi-major axis.
Accordingly, 2a = 26 ⇒ a = 13 and c = 5.
It is known that.
Thus, the equation of the ellipse is.
Question 16:
Find the equation for the ellipse that satisfies the given conditions: Length of minor axis 16, foci (0, ±6)
Answer:
Length of minor axis = 16; foci = (0, ±6).
Since the foci are on the y-axis, the major axis is along the y-axis.
Therefore, the equation of the ellipse will be of the form, where a is the semi-major axis.
Accordingly, 2b = 16 ⇒ b = 8 and c = 6.
It is known that.
Thus, the equation of the ellipse is.
Question 17:
Find the equation for the ellipse that satisfies the given conditions: Foci (±3, 0), a = 4
Answer:
Foci (±3, 0), a = 4
Since the foci are on the x-axis, the major axis is along the x-axis.
Therefore, the equation of the ellipse will be of the form, where a is the semi-major axis.
Accordingly, c = 3 and a = 4.
It is known that.
Thus, the equation of the ellipse is.
Question 18:
Find the equation for the ellipse that satisfies the given conditions: b = 3, c = 4, centre at the origin; foci on the x axis.
Answer:
It is given that b = 3, c = 4, centre at the origin; foci on the x axis.
Since the foci are on the x-axis, the major axis is along the x-axis.
Therefore, the equation of the ellipse will be of the form, where a is the semi-major axis.
Accordingly, b = 3, c = 4.
It is known that.
Thus, the equation of the ellipse is.
Question 19:
Find the equation for the ellipse that satisfies the given conditions: Centre at (0, 0), major axis on the y-axis and passes through the points (3, 2) and (1, 6).
Answer:
Since the centre is at (0, 0) and the major axis is on the y-axis, the equation of the ellipse will be of the form
The ellipse passes through points (3, 2) and (1, 6). Hence,
On solving equations (2) and (3), we obtain b2 = 10 and a2 = 40.
Thus, the equation of the ellipse is.
Question 20:
Find the equation for the ellipse that satisfies the given conditions: Major axis on the x-axis and passes through the points (4, 3) and (6, 2).
Answer:
Since the major axis is on the x-axis, the equation of the ellipse will be of the form
The ellipse passes through points (4, 3) and (6, 2). Hence,
On solving equations (2) and (3), we obtain a2 = 52 and b2 = 13.
Thus, the equation of the ellipse is.