NCERT Solutions for Class 12 Maths Chapter 7 – Integrals Ex 7.2
Page No 304:
Question 1:
Answer:
Let = t
∴2x dx = dt
Question 2:
Answer:
Let log |x| = t
∴
Question 3:
Answer:
Let 1 + log x = t
∴
Question 4:
sin x ⋅ sin (cos x)
Answer:
sin x ⋅ sin (cos x)
Let cos x = t
∴ −sin x dx = dt
Question 5:
Answer:
Let
∴ 2adx = dt
Question 6:
Answer:
Let ax + b = t
⇒ adx = dt
Question 7:
Answer:
Let
∴ dx = dt
Question 8:
Answer:
Let 1 + 2x2 = t
∴ 4xdx = dt
Question 9:
Answer:
Let
∴ (2x + 1)dx = dt
Question 10:
Answer:
Let
∴
Question 11:
Answer:
Let I=∫xx+4 dxput x+4=t⇒dx=dt
Now, I=∫t-4tdt=∫t-4t-1/2dt=23t3/2-42t1/2+C=23.t.t1/2-8t1/2+C=23x+4x+4-8x+4+C
=23xx+4+83x+4-8x+4+C=23xx+4-163x+4+C
=23x+4x-8+C
Question 12:
Answer:
Let
∴
Question 13:
Answer:
Let
∴ 9x2 dx = dt
Question 14:
Answer:
Let log x = t
∴
Question 15:
Answer:
Let
∴ −8x dx = dt
Question 16:
Answer:
Let
∴ 2dx = dt
Question 17:
Answer:
Let
∴ 2xdx = dt
Page No 305:
Question 18:
Answer:
Let
∴
Question 19:
Answer:
Dividing numerator and denominator by ex, we obtain
Let
∴
Question 20:
Answer:
Let
∴
Question 21:
Answer:
Let 2x − 3 = t
∴ 2dx = dt
⇒∫tan22x-3dx = ∫sec22x-3 – 1dx=∫sec2t- 1dt2= 12∫sec2t dt – ∫1dt= 12tant – t + C= 12tan2x-3 – 2x-3 + C
Question 22:
Answer:
Let 7 − 4x = t
∴ −4dx = dt
Question 23:
Answer:
Let
∴
Question 24:
Answer:
Let
∴
Question 25:
Answer:
Let
∴
Question 26:
Answer:
Let
∴
Question 27:
Answer:
Let sin 2x = t
∴
Question 28:
Answer:
Let
∴ cos x dx = dt
Question 29:
cot x log sin x
Answer:
Let log sin x = t
Question 30:
Answer:
Let 1 + cos x = t
∴ −sin x dx = dt
Question 31:
Answer:
Let 1 + cos x = t
∴ −sin x dx = dt
Question 32:
Answer:
Let sin x + cos x = t ⇒ (cos x − sin x) dx = dt
Question 33:
Answer:
Put cos x − sin x = t ⇒ (−sin x − cos x) dx = dt
Question 34:
Answer:
Question 35:
Answer:
Let 1 + log x = t
∴
Question 36:
Answer:
Let
∴
Question 37:
Answer:
Let x4 = t
∴ 4x3 dx = dt
Let
∴
From (1), we obtain
Question 38:
equals
Answer:
Let
∴
Hence, the correct answer is D.
Question 39:
equals
A.
B.
C.
D.
Answer:
Hence, the correct answer is B.